Its 4x^2 ≥ 13x -3
I hate yahoo. Thats a >= sign.
2007-04-08 11:51:20 · 6 answers · asked by TICKLES 1 in Science & Mathematics ➔ Mathematics
4x^2 ≥ 13x -3
4x^2 -13x +3 ≥ 0
factor
(4x^2 -1x) + (-12x+3) ≥ 0
x(4x - 1) + -3(4x - 1) ≥ 0
(x-3)(4x-1) ≥ 0
since the equaiton opens up
x ≤ 1/4 or x ≥ 3
2007-04-08 12:01:59 · answer #1 · answered by 7 · 0⤊ 0⤋
4x^2 ⥠13x -3
4x^2-13x+3>=0
(4x-1)(x-3)>=0
x>= 1/4, 3
2007-04-08 18:58:34 · answer #2 · answered by jaybee 4 · 0⤊ 0⤋
4^2>= 13x-3
-13x-3
4^2-13x-3>=0
+3
4^2-13x>=3
16
16-13x>=3
-16
-13x>= -13
/-13x
X<=1
2007-04-08 19:03:26 · answer #3 · answered by Anonymous · 0⤊ 0⤋
First make it equal to zero and solve to get the two roots. Then try a point to the left of the lower root; a point between the roots, and a point to the right of the higher root. Whichever section(s) works, that's where the solution set is
2007-04-08 19:04:46 · answer #4 · answered by hayharbr 7 · 0⤊ 0⤋
4x^2-13x+3>= 0
(4x-1)(x-3)>=0
x 1/4;3>=0
2007-04-08 18:58:01 · answer #5 · answered by Dave aka Spider Monkey 7 · 0⤊ 2⤋
im not gonna answer i just want to ask if ^2 means SQUARED
2007-04-08 18:58:44 · answer #6 · answered by Anonymous · 0⤊ 1⤋