how do you solve (4b+8/c^2d^2)/(b+2/c^4d^2)?

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I need help with my math homework!! Is anyone sure about this problem?

2007-04-08 11:32:17 · 2 answers · asked by BABY J 20 1 in Science & Mathematics ➔ Mathematics

4b+8/ c^2d^2 / b+2/ c^4d^2

4b+8/c^2d^2 * c^4d^2/b+2

4(b+2)/c^2d^2 * c^4d^2/b+2

b+2;d+2cancel out c^2 becomes 1 and c^4 becomes c^2

4c^2---answer

2007-04-08 11:51:57 · answer #1 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋

You use the distributive property. 4b * (b+2/c^4d^2)
8/c^2*(b+2/c^4^2) and d^2*(b+2/c^4^2), put it all together, and you're good.

2007-04-08 11:38:08 · answer #2 · answered by Kirstin 3 · 0⤊ 0⤋