math problem--please help?

Question

a woman at the zoo said to a clown that we're having a problem with WB's at this moment.she said:16and 2/3% WB'sof the zoo's 150 WB's had become infected with fleas, ticks or both. last week she sent her 2 assistants Orly and Willy to count the # of WB's w/ fleas and the number of ticks, & the # of both ticks & fleas. they didn't follow her directions and determined only that 20 WB's have fleas, and 14 WB's have ticks. The woman said she would have to re-examine all 150 WB's to determine how many have only fleas, how many have only ticks, and how many have both fleas & ticks.

please help the clown impress the woman by determing the number of infected WB's in each catagory.

please if you can, show all your work.

thank you

Answer 1

okay, first off you know 16.667% of 150 are infected. so that tells you that 25 are infected.

of those 25, 20 have fleas, and 14 have ticks. (given)
F=Number with just fleas
T=Number with Just ticks
B=Number with Ticks and Fleas

25=F+T+B
F+B=20
T+B=14

solve for B

25=(20-B)+(14-B)+B
25=34-B
-B=-7
B=7

substitute and solve
F+7=20
F=13

T+7=14
T=7

so, you have 13 with Fleas only, 7 with Ticks only, and 7 with both fleas and ticks.

Answer 2

.166666*150=25 infected wombats. Since 20 have fleas and 14 have ticks and 20+14=34...9 of the wombats must have ticks and fleas so that a total of 25 have at least one of them.

Answer 3

first find 16 and 2/3% of 150 = 25
so 25 are infected
and thats all i understand
sorry

Answer 4

umm is this for like ratios, unit rates, solving equations, the distributive property, scale drawing, or like mean, median, mode??????? email me wat @ [e-mail]

Answer 5

wow...good luck.