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I've been working on this problem all day (it is part of a definite integral word problem) and I have been trying to match up the answer with the answer I get in Maple. I never seem to come out right. I think the error is in my integration. I'm trying to integrate:
Pi*sqrt(y)*sqrt(4+(1/y))

Any advice is appreciated. Thanks

2007-04-08 09:48:32 · 3 answers · asked by AlaskaGirl 4 in Science & Mathematics Mathematics

3 answers

integral pi sqrt(y) sqrt(4+1/y) dy
= integral pi sqrt( 4y+1) dy
= (2/3)(1/4) pi (4y+1)^(3/2) + const

2007-04-08 09:58:14 · answer #1 · answered by hustolemyname 6 · 0 0

First, let's simplify the formula:

∫π√y√(4+1/y) dy

Becomes:

π∫√(4y+1) dy

Let us make the substitution u=4y+1, du=4 dy:

π/4 ∫√u du

Which integrates trivially as:

π/6 * u^(3/2) + C
π(4y+1)^(3/2)/6 + C

And we are done.

2007-04-08 17:02:21 · answer #2 · answered by Pascal 7 · 0 0

try this link on calculus help.. it should be in there okay!

2007-04-08 16:52:47 · answer #3 · answered by cheerio_luver538561 2 · 0 0

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