x = first pipe
x + 12 = second pipe
15 = total hours for both pipes
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x + x + 12 = 15
2x + 12 = 15
2x + 12 - 12 = 15-12
2x = 3
2x / 2 = 3 / 2
x = 3/2
x = 1 1/2
x = 1.5
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x + x + 12 = 15
1.5 + 1.5 + 12 = 15
1.5 + 13.5 = 15
15 = 15
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The first pipe will take 1.5 hours
The secoe pipe will take 13.5 hours
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2007-04-08 09:04:15
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answer #1
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answered by SAMUEL D 7
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This is a solvable problem, but you need to be careful how you do it. First of all, EACH pipe will take LONGER than 15 hours to fill the tub since the two pies together take 15 hours.
volume = rate x time
each pipe has a different rate (r1, r2) and time (t1,t2) to fill the same tub.
And t2 = t1 +12
vol = (r1+r2)15 = r1xt1 = r2(t1+12)
You have two equations in 2 unknowns (r1,r2). Use these to eliminate both. You will end up with a quadratic equation for t1. Solve that and pick the answer that is LONGER than 15 hours. The second pipe with take 12 hours longer than this answer.
Hope this helps. Good luck!
2007-04-08 16:28:29
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answer #2
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answered by Scott H 3
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Sorry, no one has yet posted the right answer
to this problem!
Let's do it another way.
I like to figure out what happens in 1 hour.
So if the faster pipe can do the job in x hours
it can do 1/x of it in 1 hour.
Also, the slower pipe can do 1/(x+12) of it in 1 hour.
So our equation for this problem is
1/x + 1/(x+12) = 1/15.
This gives
x + x + 12 = x(x+12)/15.
2x + 12 = (x²+12x)/15.
30 x + 180 = x² + 12x
x² -18x -180 = 0.
Now we solve by quadratic formula
x = (1/2)*(18 + â1044),
neglecting the negative answer.
Simplifying, we find
x = 9 + 3â29 or about 25.155 hrs
x + 12 = 21 + 3â29 or about 37.155 hrs.
Check: The reciprocals of these radicals add
up to 1/15.
2007-04-08 17:09:14
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answer #3
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answered by steiner1745 7
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Ok. so first all together the pipes take 15 hrs. 1 pipe takes y+12. so 15=y+(y+12), 15-12 equals 3. So y+y=3. One of the pipes takes 1.5 hrs, and the other pipes takes 13.5 hrs.
2007-04-08 15:24:14
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answer #4
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answered by Anonymous
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The form is:
a/b + c/d = 1
where b and d are the times each takes to do the job alone, and a and c are the times each actually works, so we have
15/x + 15/(x+12) = 1
15(x+12) + 15x = x(x+1)
30x + 180 = x² + x
x² - 29x - 180 = 0
(x-30)(x+1) = 0
x = 30 hrs. [ignoring x=-1]
x+12 = 42 hrs.
2007-04-08 15:22:55
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answer #5
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answered by Philo 7
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If you use 2x(the faster pipe) to fill 2 washtubes (1 faster-pipe for 1 tub) it will cost 12hrs less than using those 2 pipes to do the same thing ( the faster for 1st tub and the slower for 2nd tub)
=> it cost 15-12= 3hrs for the faster to fill 2 tube
=> it cost 3/2=1.5hrs for the faster pipe
=> it cost 1.5+12=13.5 hrs for the slower pipe.
Good luck!
2007-04-08 15:37:35
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answer #6
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answered by Sư Ngố 4
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Well if you take away 12 hours from 15 hours, you are left with two. Divide this by two and you're left with 1.5. So one of the pipes would fill the bathtub in one and a half hours and the other would fill up the tub in 13 and a half hours. Hope this helps, best answer please.
2007-04-08 15:20:16
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answer #7
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answered by sweet_angel92 3
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26 hours. But then if you did not do your own homework, how would you know?
2007-04-08 15:22:55
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answer #8
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answered by Someone who cares 7
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do your own homework how will you get your grades up to par
2007-04-08 15:20:56
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answer #9
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answered by jim m 7
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No, I won't do it.
2007-04-08 15:19:37
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answer #10
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answered by Anonymous
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