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Find f'(x).

f(x) = xe^(-2x)



This is what I did:

u = x
du = 1
v = e^(-2x)
dv = -2e^(-2x)

(x) (-2e^(-2x)) + (e^(-2x)) (1)

That got me:
-2xe^(-2x) + e^(-2x)


Is that correct?

2007-04-08 07:30:19 · 2 answers · asked by Rita 3 in Science & Mathematics Mathematics

2 answers

Absolutely correct!!
Perfect application of the product rule.

The only thing I would change is in your answer, start with
f '(x) = ...
so that it's clear what you have in mind.

2007-04-08 07:35:17 · answer #1 · answered by jim n 4 · 0 0

It is correct

2007-04-08 15:19:30 · answer #2 · answered by santmann2002 7 · 0 0

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