please please help me !!!!
i need the nth term
4,9,16,25,36
2007-04-08 07:11:36 · 11 answers · asked by barcaroni2009 1 in Science & Mathematics ➔ Mathematics
(n+1)^2
They are just perfect squares.
2007-04-08 07:14:41 · answer #1 · answered by John T 6 · 2⤊ 0⤋
It is an arithmetical progression but with the difference d itself increasing by 2 each time.
First Term = 4 = 2^2
Second term = 4 + 5 = 9 = 3^2
Third Term = 4 + 5 + 7 = 16 = 4^2
Fourth term = 4 + 5 + 7 + 9 = 25 = 5^2
Fifth term = 4 + 5 + 7 + 9 + 11= 36 = 6^2
nth term = 4 + 5 + 7 + 9 + ......... + (2n + 1) = (n + 1)^2
2007-04-08 07:20:30 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
First find the pattern in the sequence of numbers squares of numbers. 4 is 2 squared, 9 is 3 squared, and so on. So the nth term is (n+1)^2, because the 1st term is 2 squared.
2007-04-08 07:24:55 · answer #3 · answered by Anonymous · 0⤊ 0⤋
The nth term is (n+1)^2
2007-04-08 07:15:41 · answer #4 · answered by Scott H 3 · 0⤊ 0⤋
4 9 16 25 36
The pattern
4 + 5 = 9
9 + 7 = 16
16 + 9 = 25
25 + 11 = 36
36 + 13 = 49
- - - - - - -s-
2007-04-08 07:23:19 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋
the sequence is r^2
next term is 7^2 = 49
if it were not easy to spot you could have taken differences
1st = 5, 7, 9, 11
2nd = 2,2,2
which would tell you that the sequence terms were a+br+cr^2 and its easy to look at first terms to determine a,b,c
2007-04-08 07:17:11 · answer #6 · answered by hustolemyname 6 · 0⤊ 0⤋
49
2007-04-08 07:14:55 · answer #7 · answered by dr. shan 4 · 0⤊ 0⤋
you just keep adding the number by the next odd integer....
ex.) 4+5 = 9
9+7= 16
16+9 = 25
25 + 11 = 36
2007-04-08 07:17:16 · answer #8 · answered by iamerica329 1 · 0⤊ 0⤋
2^2 = 4
3^2 = 9
4^2 = 16
5^2 = 25
6^2 = 36
and the next number would be
7^2 = 49
so on...
2007-04-08 07:15:07 · answer #9 · answered by 7 · 1⤊ 0⤋
all you are doing is squaring the first few #
so it;s 49
2007-04-08 07:19:54 · answer #10 · answered by Bob, Computer ADDICT. 3 · 0⤊ 0⤋