16. Calculus Help.....?

Question

Using substitution x = 2t + 1, which of the folloing is equivalent to integralfrom 0 to 3 4th root (2t+1) dt

A. integral 0 to 3 4th rt (x) dx
B. 1/2 integral 0 to 3 (x)dx
C. integral -.5 to 1 4th rt (x) dx
D. integral 1 to 7 4th rt (x) dx
E. 2 integral 1 to 7 4th rt (x) dx

Answer 1

answer should be E. as t goes from 0 to 3, x goes from 1 to 7. Don't forget to relate dx to dt. to convert the expression you've got to use dx = 2dt.

are you sure you wrote down E correctly? x = 2t + 1 gives you dx = 2dt => dt = dx/2,

so the 2 in E should be 1/2 as mjivden points out.

Answer 2

I think the closest answer is E, but I think the correct set-up is:

1/2 integral from 1 to 7 4th root (u) du