B/c there is like a ba-zillion more molecules in the same volume.
It's like the old joke: what weighs more, a ton of feathers or a ton of bricks? A ton of feathers has the same mass as a ton of bricks, but would take up a WHOLE LOT more space.
2007-04-07 21:20:58
·
answer #1
·
answered by P-nuts and Hair-dos 7
·
0⤊
0⤋
Your statement is not true.
Solid and gas of the same substance has the same mass.
If you say a solid has more mass than it's gas state, it must be that the gas has escaped once it was turned to gas form.
But if you really say about the real mass, they have the same mass from the same volume.
You can try by using a beaker, put 1 ice cube in the beaker. Keep the beaker in a balance. Heat it until the ice vapourizes into gas. And check the reading at the balance. It's still same. But remember to keep the opening of the beaker close as tight as possible. Do not let the gas escape after the water evaporates.
2007-04-07 21:42:49
·
answer #2
·
answered by brad 3
·
0⤊
0⤋
solid has a more density because the particles constituting solid are more tightly packed then the particles constituing the gas so the mass of the solid is more
2007-04-07 21:22:22
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
In a solid, the particles are much closer together than in a gas, so the density is higher.
2007-04-07 21:16:33
·
answer #4
·
answered by Gervald F 7
·
0⤊
1⤋
solid materials are more dense and would then be heavier than gas with the same volume
2007-04-07 21:17:14
·
answer #5
·
answered by kapayapaan 1
·
0⤊
0⤋
It's the difference in their molecular structure.
Molecules of solids are bonded very tightly together. (Higher density).
Gas molecules move around freely in the space they occupy.
2007-04-07 21:22:00
·
answer #6
·
answered by Norrie 7
·
0⤊
0⤋
heat up a solid it will EXPAND and turn into a liquid, Heat up a liquid and it will EXPAND and turn into a gas........
2007-04-07 21:40:26
·
answer #7
·
answered by stephencaddy 1
·
0⤊
0⤋
bacause a gas can be compressed
2007-04-07 21:16:05
·
answer #8
·
answered by Lee 5
·
0⤊
2⤋