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what is the LCD and how can it be simplied

2007-04-07 18:47:37 · 7 answers · asked by Ai Ling Z 1 in Science & Mathematics Mathematics

7 answers

the LCD is the least common denominator.

I think what you mean is:
y/(y-3) +6/(y+3) = 1;

The LCD is the product of the two denominators:
LCD = (y-3)(y+3) = y² - 3² = y² - 9;

2007-04-07 18:50:22 · answer #1 · answered by Esse Est Percipi 4 · 0 0

the lcd is the two denominators multiplied

(y-3)(y+3) or y^2 -9

multiply that to the top of each.

then combine everything and put it all over (y^2 - 9)
then bring over whatever the 1 comes out to be (which is (y^2-9)/(y^2-9) to the other side.
then combine that.
simplify.

2007-04-08 01:53:23 · answer #2 · answered by Anonymous · 0 0

1. You have to multipy both sides of the equation by the common denominator ((y-3)(y+3))
2. Your equation then becomes:
y^2+3y+6y-18 = y^2-3y+3y-9
3. 9y-18=-9
4. 9y-9=0
5. 9(y-1)=0
solve for y
y = 1

2007-04-08 02:18:04 · answer #3 · answered by Hleigh 1 · 0 0

LCD is (y-3)(y+3)=y^2-9

y(y+3)+6(y-3)=Y^2-9
y^2+3y+6y-18=y^2-9
y^2+9y-18=y^2-9
y^2-y^2+9y-18+9=y^2-y^2-9+9
9y-9=0
9y-9+9=0+9
9y=9
y=1

2007-04-08 05:22:08 · answer #4 · answered by Dave aka Spider Monkey 7 · 0 0

y/(y-3)+6(y+3)=1

y(y-3)/(y-3)+6(y-3)/(y+3)

= (y-3)(y+3)

y(y-3)(y+3)+6(y-3)(y+3)

= (y-3)(y+3)

y(y+3)+(6y-18)(y+3)=y²-9

y(y+3)+(6y-18)=y²-9

y²+3y+6y-18=y²-9

y²-y²+9y=18-9

9y=9

y=1



by checking this, we have:

1/(y-3)+6/(y+3) = 1

1/(1-3)+6/(1+3)=1

-1/2+ 1½=1

1= 1

LHS = RHS, correct.

2007-04-08 02:18:14 · answer #5 · answered by edison c d 4 · 0 0

Do your own homework!

2007-04-08 01:50:21 · answer #6 · answered by Anonymous · 0 2

if you say so.......

2007-04-08 01:50:16 · answer #7 · answered by rose_merrick 7 · 0 2

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