x^4/4
2007-04-07 14:43:07 · 5 answers · asked by m s 1 in Science & Mathematics ➔ Mathematics
y=x^4 / 4
ex: y=4 /x^4
y'= 4(-4x^-5) = -16 /x^5
2007-04-07 14:59:09 · update #1
The derivative of x^n is n*x^(n-1)
Thus...
First derivative: 4 * x^3/4 = x^3
Second derivative: 3*x^2
Third: 6*x
Fourth: 6
2007-04-07 14:46:57 · answer #1 · answered by tedfischer17 3 · 0⤊ 0⤋
1st derivative 4x^3 / 4 = x^3
2nd : 3*x^2
3rd : 6
2007-04-07 21:47:11 · answer #2 · answered by gp4rts 7 · 0⤊ 1⤋
If I'm understanding you correctly, that's a very easy question.
y = x^4/4
y' = x^3
y'' = 3x^2
y''' = 6X
y'''' = 6
every other derivative = 0
2007-04-07 21:48:01 · answer #3 · answered by Dr D 7 · 0⤊ 0⤋
y´= 4x^3/4 =x^3 ????
2007-04-07 21:47:12 · answer #4 · answered by santmann2002 7 · 0⤊ 0⤋
y = (x^4)/4
y' = (4x^3)/(4) = x^3
y'' = 3x^2
y''' = 6x^1
y'''' = 6x^0
y''''' = 0
2007-04-07 21:57:08 · answer #5 · answered by Mark 6 · 0⤊ 0⤋