if you have 6 different herbs???

Question

hi my ? is this im playing a game that you can make different stews .I have 6 different herbs and each stew takes 3 what are the combinations?

Answer 1

6 x 5 x 4
------------ = 20
1 x 2 x 3

The order of the herbs doesn't matter, so you have to divide by 1 x 2 x 3

Answer 2

You can choose any of 6 for the first, 5 for the second and 4 for the third. This gives you 6 * 5 * 4 = 120 combinations. But some of these combos are the same, like salt, sage, thyme and sage, salt, thyme. So, you have to reduce 120 by the number of duplicates which turns out to be 3*2*1 = 6.
The final answer is 120 / 6 = 20

Answer 3

This is combination (the order is not important) of six elements taken three at a time. The number of combinations is 6! divided by 3!*(6-3)! = 20.

Answer 4

There are 20 ways to choose three herbs, 6 choose 3. There are 6x5x4 ways to choose them, but everyone can be chosen 3x2x1, 6 ways, so divide by six, u get 20 ways.

Hope this Helps!!

Answer 5

I don't really understand your question. You want a list of possible combinations? Or you want the number of possible combinations?

Whoa...my initial answer was wrong - very sorry about that
It is simply "6 choose 3" (you can do this on your calculator by pressing 6, nCr, 3).
The answer is then 20.

Answer 6

20 combinations

Answer 7

You would refer to this as "6 choose 3". Answer is 20.

Check out:

http://mathforum.org/dr.math/faq/faq.comb.perm.html

Answer 8

16 combinations is what you have

Answer 9

20 WAYS

Answer 10

54 combinations..