Factor. 18x^2 + 67x + 14?

Answer 1

The factors of 18
6*3 9*2 18*1

The factors of 14
14*1 7*2

Look for combinations that could add up to 67
like try 6*3 and 14*1
6 times 14 = 84 and 3 times 1 = 3 84 and 3 do not equal 67

try 9*2 and 7*2
9 times 7 = 63 2 times 2 = 4 63 and 4 equal 67
so those are the numbers you need to use

(9x + 2)(2x + 7) is your answer

Answer 2

I recommend the quadratic formula...

D = Square root (b^2 - (4 * a * c))

1st number = (-b + D) / (2 * a)
2nd number = (-b - D) / (2 * a)

a is always the coefficient with the x^2 (in this case 18)
b is always the coefficient with x (in this case 67)
c never has a variable (in this case 14)

Then just place them here
(x - 1st number)(x - 2nd number)

***NOTE***
The minus sign in front of the b and after the x just means that you are suppose to change the sign of whatever number you are using (i.e. 18 so you use -18)

D = Square Root (67^2 - (4 * 18 * 14)) = 59
1st number = (-67 + 59) / (2 * 18) = -2/9
2nd number = (-67 - 59) / (2 * 18) = -7/2

(x + 2/9)(x + 7/2)

Answer 3

(2x+7)(9x+2)