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integral from 0 to 1 of x dx / ( x^2 + 1) is = to

2007-04-07 14:26:10 · 2 answers · asked by jpatel10989 1 in Science & Mathematics Mathematics

2 answers

Int = 1/2 ln(x^2+1) between (0 and 1) = 1/2(ln 2)

2007-04-07 14:34:38 · answer #1 · answered by santmann2002 7 · 0 0

Integral (0 to 1, 1/(x^2 + 1) dx )

This is a known derivative; it's the derivative of arctan.

arctan(x) {evaluated from 0 to 1}

arctan(1) - arctan(0)

arctan(1) is equal to pi/4 (since tan(pi/4) = 1), and arctan(0) is equal to 0 (since tan(0) = 0).

pi/4 - 0

pi/4

EDIT: I read the question incorrectly. The answerer below has it correct.

2007-04-07 21:31:08 · answer #2 · answered by Puggy 7 · 0 0

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