lim h --> 0 (pi/2 + h) / (h) is?

Answer 1

Nonexistent. When given a limit of the form c/0, where c is any nonzero number, the limit of the absolute value is always infinity. Since approaching from the right, the denominator is positive, [h→0⁺]lim (π/2 + h)/h = ∞ and similarly, approaching from the left the denominator is negative, so [h→0⁻]lim (π/2 + h)/h = -∞. For the limit to exist, the two one-sided limits would have to be the same, and they are not, so the limit does not exist.

Answer 2

If h tends to 0+, you get +oo. If h tends to 0-, then you get - oo

So, since both lateral limits are different you dont have a limit

Ana