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If the dc base current of a transistor with an hFE of 51 is 87 mA, then the approximate value of re’ is ________ohms

2007-04-07 12:25:05 · 1 answers · asked by sam19090 1 in Science & Mathematics Physics

1 answers

For a silicon bipolar junction transistor (BJT) transistor I would say Vbe=.7v and then
Re=Vbe / Ie
Re= .7v/[(51+1) 87E-3]
Re=0.155 ohms

2007-04-07 17:38:31 · answer #1 · answered by Edward 7 · 0 0

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