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cos(x + π/2) = -sinx

cos^4x - sin^4x = cos2x

sinx secx = tanx

2007-04-07 11:29:21 · 2 answers · asked by camillesays 2 in Science & Mathematics Mathematics

2 answers

cos(x + π/2) =
cos x cos π/2 - sin x sin π/2 =
cos x (0) - sin x (1) =
-sin x

cos^4 x - sin^4 x =
(cos² x + sin² x)(cos² x - sin² x) =
(1)(cos² x - sin² x) =
cos 2x

sin x sec x =
sin x (1/cos x) =
(sin x)/(cos x) =
tan x

2007-04-07 11:39:46 · answer #1 · answered by Philo 7 · 0 0

Quite simple, actually:

cos (x+π/2) = cos x cos (π/2) - sin x sin (π/2) = cos x * 0 - sin x * 1 = -sin x

cos⁴ x - sin⁴ x = (cos² x - sin² x)(cos² x + sin² x) = (cos (2x))(1) = cos (2x)

sin x sec x = sin x * 1/cos x = tan x

2007-04-07 18:36:47 · answer #2 · answered by Pascal 7 · 0 0

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