2x + 5y = 10
a.-2/5
b.-1/3
c.-5/2
d.no slope
3x -5 = 0
a.5/3
b.-5/3
c.3/5
d.no slope
thnks for tha help!!
2007-04-07 10:56:51 · 5 answers · asked by skate_freely 1 in Science & Mathematics ➔ Mathematics
2x + 5y = 10
2x + 5y - 2x = - 2x + 10
5y - 2x + 10
5y / 5 = - 2x/5 + 10/5
y = - (2.5)x + 2
The slope is - 2/5
-- - - - - - - -- -
The second problem
no slope
- - - - - - - -s-
2007-04-07 12:13:08 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
Take the equation for a straight line: y=a+bx
rearrange 2x + 5y = 10 to get:
5y=10-2x (now divide both sides by 5.
y=2-(2/5)x
2 is the intercept of the line on the y axis
-2/5 is the slope.
in the the second example 3x=5 so x=(5/3) ...no slope
2007-04-07 11:10:15 · answer #2 · answered by Chris 1 · 0⤊ 0⤋
General equation of a line is
mx + b = y
where m is the slope and b is the y intercept
Rearrange your equation to get it in the general form
2x + 5y = 10
2x - 10 = -5y
(-2/5)x + 2 = y
So, -2/5 is the slope or answer a.
You can do the other one applying the same principles.
2007-04-07 11:04:19 · answer #3 · answered by zeb 4 · 0⤊ 1⤋
change the equation around so that it's in the slope intercept form - y=mx+a then m is the slope.
2x+5y=10
5y = -2x + 10
y = -(2/5) x + 2. Therefore, the slop is -(2/5) (a)
3x-5=0
x = 5/3 there is no 'y', therefore, it's a verticle line which has no slope (undefined) (d)
2007-04-07 11:03:51 · answer #4 · answered by bz2hcy 3 · 0⤊ 0⤋
a.) second question slope=3
2007-04-07 11:07:00 · answer #5 · answered by dwinbaycity 5 · 0⤊ 0⤋