Chemistry question....plz help!!!!?

Question

If you combine 75.0 mL of 0.350 M of HCl and an excess of Na2CO3, what mass of CO2 in grams should be produced? The balanced equation is given:
Na2CO3 + 2HCl => 2NaCl + H2O + CO2

Answer 1

First find how many moles of HCl you have:
= 75.0ml x 1L/1000mL x 0.350 (moles/L)
= #moles HCl, sorry i dont have a calculator handy

then, since it takes 2 moles of HCl to produce 1 mole of CO2, you would find how many moles of CO2 you have:
= [#moles HCl (from above)] x [1 mole CO2 / 2 moles HCl]
= #moles CO2

Lastly, you find how many grams of CO2 is produced
= [#moles CO2] x [44.0 grams CO2 (use periodic table) / 1 mole CO2]
= YOUR ANSWER!!!

So overall:
75 x (1/1000) x 0.350 x (1/2) x 44= ______

Hope this helps.

Answer 2

(75 x 0.35/1000) x 44