Solve for x?

Question

2x^2-14x+12=0 Hint: Use by factoring, graphing, quadratic formula, possible imaginary #'s

Answer 1

2x² - 14x + 12 = 0

2x² - 2x - 12x + 12 = 0

2x(x - 1) - 12(x - 1) = 0

(2x - 12)(x - 1)

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roots

2x - 12 = 0

2x - 12 + 12 = 0 + 12

2x = 12

2x / 2 = 12 / 2

x = 12 / 2

x = 6

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Roots

x - 1 = 0

x - 1 + 1 = 0 + 1

x = 1

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Quadratic formula

x = - b ± √b² - 4ac / 2a

x² - 14x + 12 = 0

a = 2

b = - 14

c = 12

x = - (- 14) ± √(- 14) - 4(2)(12) / 2(2)

x = 14 ± √196 - 96 / 4

x = 14 ± √100 / 4

x = 14 ± 10 / 4

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Solving for +

x = 14 + 10 / 4

x = 28 / 4

x = 6

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Solving for -

x =14 - 10 / 4

x = 4 / 4

x = 1

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Answer 2

Factor out the 2, so you get 2(x^2-7x+6)=0, which then becomes 2(x-6)(x-1)=0. Solve each piece: x-6=0 and x-1=0 So, x=1 and x=6 are the two answers.

Answer 3

First, you can divide the whole equation by 2

x^2 - 7x + 6 = 0

Then you have a few options.
Factor
(x-1)(x-6) = 0
x = 1 or 6

Use quadratic formula
x = (-b+/-sqrt(b^2 - 4 x a x c))/2a
x = (7 +/-sqrt(49 - 4 x (1) x (6))/2
x = 7/2 + 5/2 or 7/2 - 5/2
x = 1 or 6

Answer 4

x=1 and x=6

Answer 5

2X^2-14x+12=0

solution goes this way....

2X^2-14x+12=0

2X^2-12x-2X+12=0(here the two factors are 12 nd 2)

2X(X-6) -2(X-6)=0

(x-6) (2X-2)

so the value of X is 6 and 1
as X-6=0 gives X=6 nd 2X-2=0 which gives X= 1

Answer 6

If you want to, you can first simplify it by removing the common factor 2. you then get:
x^2 - 7x + 6 = 0

Either factor it as (x-6)(x-1) = 0
and set each term to 0

or use the quadratic formula (-b +/- sqrt(b^2-4ac)/2a

Answer 7

2x^2-14x+12=0
divide by 2
x^2-7x+6 =0
(x-6)(x-1)=0
x = 6, 1

Answer 8

divide by 2

x^2 -7x +6 =0

factor
(x-1)(x-6) = 0

x-1 = 0 so x = 1
x-6 = 0 so x = 6

the answer is x=1 and x=6

Answer 9

2(x^2-x)-12(x+1)=0

2(x^2-x)=12(x+1)

(x^2-x)=6(x+1)

x^2-x=6x+6

x^2-7x-6=0

x^2-x-6x-6=0

x(x-1)- 6(x-1)=0

(x-1)(x-6)=0

x=1 or x=6

Answer 10

x² - 7x + 6 = 0

(x-6)(x-1) = 0

x = 1, or 6