Wade can paint a room in 4 hours and Jan can paint the same room in 7 hours. How long can both paint the room?

Answer 1

x/4 + x/7 = 1

28(1/4) + 28(x/7) = 28(1)

7x + 4x = 28

11x = 28

11x ? 11 = 28 / 11

x = 28 / 11

x = 2 6/11

x = 2 hours 32 minutes 43 seconds

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Answer 2

Well, if we want them both to paint the room, they need the same amount of time. Let's see what they can each do in an hour: Wade can paint 1/4 of a room in an hour, and Jan paints 1/7 of a room in an hour, so they can both paint 1/4+1/7 or 11/28 of a room in an hour, but we want the time to paint 1 room, so let's make a proportion: (11/28):1::1:x [room to hours], 11x/28=1, 11x=28, x=28/11 hours, or about 2 hours 43 min and 38 sec.

Answer 3

To minimize the amount of time for the two of them to paint the room, I'd divide the room into 11 parts, and give 7 to Wade and 4 to Jan. They would finish at the same time, after 28/11 hours, or 2 hours, 32 minutes, 43.6 seconds

Answer 4

2 hours 32 minutes 43 seconds


Let the area of the room be A:

rate at which Wade works is A/4, and that of Jan is A/7.

The total rate of work is the sum, so: A/4 + A/7 = 11A/28

So the time taken is 28/11 hours.

Answer 5

wade ca do 1/4th of the work in 1 hr
jan can do 1/7th of the work in 1hr

they both can do (1/4+1/7) =11/28th of the work in 1hr
so they take 28/11 hrs or 2.54hrs to complete

Answer 6

(1/4)H + (1/7)H = 1
7H + 4H = 28
H = 28 / 11 hours
H = 2.545454545...
H = 2 hours, 32 minutes, 43+7/11 seconds

Answer 7

x/4 + x/7 = 1
7x + 4x = 28
11x = 28
x = 28/11 hours

Answer 8

Two can paint the room in 5.5 hours?