convert the rectangular equation x^2+y^2 - 2y=0 to polar form? r=2cos theta/ r=1/2costheta/ r=2sintheta/ r= -2

Answer 1

I will use @ for theta
x^2 + y^2 = 2y
r^2 = 2 (r sin @)
r = 2 sin @
Option 3 is correct

Answer 2

Convert the rectangular equation

x² + y² - 2y = 0 to polar form.

Remember the conversions between Cartesian and polar.

r² = x² + y²
y = rsinθ

Now let's convert.

x² + y² - 2y = 0

r² - 2rsinθ = 0
r² = 2rsinθ

Divide thru by r.

r = 2sinθ

Answer 3

a million. r = 4 **sq. the two factors** r^2 = sixteen **all of us understand that r^2 = x^2 + y^2** x^2 + y^2 = sixteen **you're accomplished! :D** 2. r = 6 / (2cos(-) - 3sin(-)) **Multiply the two factors with the help of a million/r** a million = 6/[2rcos(-) - 3rsin(-)] **in case you have 2 fractions = to eachother then the recipricols = to eachother** a million = [2rcos(-) - 3rsin(-)]/6 **rcos(-) = x and rsin(-) = y** a million = 2x/6 - 3y/6 **Simplify** x/3 - y/2 = a million **you're accomplished! :D**

Answer 4

r^2-2rsin@= 0 so r= 2sin@