If a compound contains 49.98% Ag 24.09% Cr 25.94% O what is emperical formula?

Question

Please help thanks

Answer 1

Here is the concept.

First assume that your sample is 100 grams, so the percentages automatically become grams of each atom.

Divide each by the respective atomic mass of that element.
For example oxygen, divide 25.94 by 16.

The resulting numbers already give you the proper ratio. But you need whole numbers. Take the smallest number and divide all 3 of the ratios by the smallest number. If you still do not have whole numbers, repeat the process.

Now you have whole numbers and you can write the empirical formula

Answer 2

element ag cr o

% 49.98 24.09 25.94
at. mass 107.9 52 16
rel. no 24.09/52 25.94/16
of moles 49.98/107.9=0.46 =0.46 =1.62

simple ratio 0.46/0.46=1 0.46/0.46=1 1.62/0.46=3
of moles

simplest whole 1 1 3
no ratio


Hence empirical formula is AgCrO3