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At room temperature, hydrogen peroxide will decompose slowly to form water and oxygen, as shown below

2H2O2-----> O2 + 2H2O

How many moles of hydrogen peroxide are used in the experiment to obtain 4800cm3 of oxygen?[one mole of any gas occupies 24.0 dm3 at room temperature?

Can u help me out with the workings too...

2007-04-07 05:05:13 · 2 answers · asked by blah,blah,blah 3 in Science & Mathematics Chemistry

2 answers

4800cm3 is 4.8 litres and hence 4.8/24 moles
This becomes .2 when you work it out.
From the equation 2 moles of peroxide make one mole of oxygen. So 0.4 are needed to make 0.2

2007-04-07 06:10:47 · answer #1 · answered by lykovetos 5 · 0 0

n = PV/RT = 1 atm * 4.8 L/(0.08206 * 298) = 0.196 moles O2

As the reaction is 2:1, you need 0.392 moles H2O2.

2007-04-07 12:11:58 · answer #2 · answered by TheOnlyBeldin 7 · 0 0

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