Solve cot x + 1 =0 for (0<= X <2pi)?

Answer 1

cot x +1 = 0
cot x = -1
cot x = 1/tan x =-1
1= - tan x
tan x = -1
tan x is negative in the 2nd and 4th quadrant. tan x = 1 for an angle pi/4 above or below the axis. therefore x = pi - pi/4 and x = 2pi - pi/4 x = 3pi/4 and 7pi/4

Answer 2

cot x= 1/tanx =-1 so tan x= -1 and x= 3pi/4 and x= 7pi/4