A says to B "i am 5 times old as u were when i was as old as u are". the sum of their present ages is 64yrs

Question

find the product of the present ages of A and B??

Answer 1

A's present age is 40
B's present age is 24
let A's present age is a, B's present age is b
so a + b = 64 (1)
The point of time "A was as old as B are" was (a-b) years ago. B was [b-(a-b)] = (2b-a) years old then.
A is "5 times old as B were" so a = 5(2b-a) <=> 6a-10b=0<=>3a-5b=0 (2)
It's easy to solve (1)&(2) and we got a=40; b=24
And the product is a x b = 960
Good luck!

Answer 2

let A's present age is A ,and B's present age is B
so A + B = 64 -------------- (1)
(A – B) years ago A was as old as B
That time B's age was B – (A – B)
Therefore A = 5( 2B – A)
or A = 10 B – 5 A
or 6 A = 10 B -------------(2)
A + B = 64 -------------- (1) Multiply this eq. by 6
6 A + 6 B = 384 -----------Putting value of 6 A = 10 B
10 B + 6 B = 384
or 16 B = 384 or B = 384 / 16 = 24
Putting this value in eq. 1
A + 24 = 64
A = 40
There product of ages = 40 × 24 = 960

Answer 3

If a and b are their ages, then a was as old as B is today a - b years ago. That time B's age was b - (a - b) = 2b - a. So, a = 5(2b - a) = 10b - 5a => 6a = 10b => b = 0.6 a.
Since a + b= 64, it follows, 1.6b = 64 => b = 64/1.6 = 40 and a = 64 - 40 = 24. And a.b = 960.

Answer 4

If a and b are their ages, then a was as old as B is today a - b years ago. That time B's age was b - (a - b) = 2b - a. So, a = 5(2b - a) = 10b - 5a => 6a = 10b => b = 0.6 a.
Since a + b= 64, it follows, 1.6b = 64 => b = 64/1.6 = 40 and a = 64 - 40 = 24. And a.b = 960.

Answer 5

A = 40 B = 24, when A was B's age, B was 8

the product of 40 and 24 is 40 x 24 = 960

Answer 6

A's present age is 40
B's present age is 24

their product is 960