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2007-04-06 23:44:22 · 9 answers · asked by gary a 1 in Science & Mathematics Mathematics

9 answers

x/3 = x^2
so x = 3x^2
so x = 0 or 1 =3x => x = 1/3

2007-04-06 23:48:19 · answer #1 · answered by hustolemyname 6 · 1 0

since
x/3 = x^2
<=>x = 3x^2
<=>0 = 3x^2 - x
<=>0 = x(3x-1)
then
3x-1=0 or x=0
<=> 3x=1
<=> x= 1/3

answer:
x= 0 or x=1/3

2007-04-07 06:57:38 · answer #2 · answered by 99%cocoa 1 · 0 0

x/3 = x^2 can also be written as-
1/3*x=x^2 then divide through by x
1/3=x

x equals 1/3

2007-04-07 06:48:48 · answer #3 · answered by Kman 2 · 0 0

I used a different aproach

x(x-1/3)=0 and i agree with the 1st,6th and 4th answerer

x=0 or x=1/3

2007-04-07 06:58:28 · answer #4 · answered by Takis 3 · 0 0

x/3 = x^2

Multiply both sides by 3,

x = 3x^2
0 = 3x^2 - x
0 = x(3x - 1)

We have two solutions.

x = { 0, 1/3}

2007-04-07 06:49:48 · answer #5 · answered by Puggy 7 · 3 0

x/3=x^2
sox^2/x=1/3
x=1/3

2007-04-07 07:00:38 · answer #6 · answered by Vp 2 · 0 0

x/3=x^2
Multiply both sides by 3
x=3x^2
0=3x^2-x
0=x(3x-1)
0=x
1/3=x

2007-04-07 07:44:17 · answer #7 · answered by Dave aka Spider Monkey 7 · 0 0

x/3=x^2
(both in LHS & RHS THERE IS AN X SO CANCEL IT)
=> X=1/3

2007-04-07 06:50:11 · answer #8 · answered by Aruna R 2 · 0 0

simple...x=1/3

2007-04-07 06:49:30 · answer #9 · answered by Ramkumar G 5 · 0 0

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