the polynomial f(x) divided by x-3 results in a quotient of x2+3x-5 with a remainder of 2.find f(3).?

Question

answers are
a.-5
b.-2
c.2
d.3

Answer 1

(x² + 3x - 5)(x - 3) + 2 = f(x)
x³ - 3x² + 3x² - 9x - 5x + 15 + 2 = f(x)
x³ - 14x + 17 = f(x)

f(3) = 3³ - 14.3 + 17
f(3) = 27 - 42 + 17
f(3) = 2


c) 2

Answer 2

Answer is c.
f(x)/x-3 = Q + 2/x-3
Multiply by x-3
f(x) = Q (x-3) + 2
If x=3, term with Q is zero.