Matrix algebra problem?

Question

Here is the problem:
[1 3 │ 5]
[0 1 │ 2] (these are brackets not straight lines on the ends of the problem and after the 2nd numbers there is a straight line)

The directions are: write the system of linear equations represented by the augmented matrix. Use x, y & z if necessary,for the variables. Ocne the system is written, us back-substitution to find it's solution.

Where do I go from here ... I have never dealt with this type of math before ... can u help me?

Please & thank you for any help, sorry I wasn't more clear before!

Answer 1

Matrices can be used to write and solve a system of equations, as is done here. All you do is put the x's in the first column, the y's in the second, and the constants in the third. This is a bit of a brief and not very good explanation, but it'll do.
So in your example, the first equation is:
1x + 3y = 5, or just x +3y = 5

and the second is:
0x + 1y = 2, or y = 2

You can then use substitution to solve the system.

Answer 2

In an augmented matrix, in any row, the entries before the vertical bar will mean the coefficients of the variables; the vertical bar means equals; and the right side will just be constants. (Separate rows mean separated equations).

With this in mind, the system of equations associated with this augmented matrix is

x + 3y = 5
y = 2

"Back-substitution" means substituting y into the first equation to find x:

x + 3(2) = 5
x + 6 = 5
x = -1.

So the solution is (x, y) = (-1, 2).

Answer 3

The vertical line in front of the last number in each line tells you you have an augmented matrix which represents the system of equations

1x + 3y = 5
0x + y = 2

The left 2/3 of the matrix is the coefficients of the variables in the system, the numbers in front of x and y.

The 2nd line tells you y = 2, so plug that in (back substitute) to the 1st equation:

x + 3(2) = 5
x + 6 = 5
x = -1

Answer 4

the numbers at the begining are the coefficients and the number after the line are the answers:

x + 3y = 5 from 1 3 I 5

y =2 from 0 1 I 2

y=2 and then x= -1

Answer 5

Your system of equations is
x + 3y = 5
0x + y = 2,
i.e. y = 2.
So x + 6 = 5
x = -1.

Answer 6

Dont hear to those fools......... first u could discover the pie 3.14 then get the cool whip to discover the denominator then u could discover an apple tree to discover the muse of the equation all of this equals...................... to ur mothers apple pie ;D