The hybridization of the central atom in NO3- is
A. p3.
B. sp2.
C. sp.
D. sp2d.
E. sp.
2007-04-06 14:47:59 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
It's sp2. The central nitrogen atom is bonded to three oxygen atoms, and has no lone pairs. If you were to draw the Lewis dot structure, one of the nitrogen-oxygen bonds would be a double bond, and the other two would be single bonds, but the three bonds can resonate with each other, so actually it's more like they're all 1 1/3 bonds. Since it's a symmetric atom with three substituents, the geometry around the central atom will be trigonal planar, and the hybridization will be sp2.
Each of nitrogen's three sp2 orbitals overlaps with the s orbital of one of the oxygen atoms. The left-over p orbital on the nitrogen is involved in a resonating double bond with the three oxygen atoms, and it basically ends up sharing three pairs of electrons between four orbitals (the p orbital of the nitrogen, and one p orbital of each of the oxygen atoms). Each oxygen atom has two more p orbitals left, which each hold a lone pair of electrons. Except I think that those lone pairs would be involved in resonance as well, so it would end up as nine pairs of electrons shared between ten orbitals, but I'm not certain of that last part.
2007-04-06 17:00:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Hybridization Of No3
2016-12-28 03:46:16 · answer #2 · answered by ? 3 · 0⤊ 0⤋
No3 Hybridization
2016-10-06 23:36:01 · answer #3 · answered by ? 4 · 0⤊ 0⤋
The nitrate ion (NO3-1) is trigonal planer with an sp2 hybridization of the nitrogen atom. All of the nitrogen electrons are employed in bonding leaving none free and because the sp2 hybrid allows for the formation of 3 regions of electrons, it is the logical choice.
2007-04-06 16:52:20 · answer #4 · answered by docrider28 4 · 0⤊ 0⤋
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RE:
The hybridization of the central atom in NO3- is?
The hybridization of the central atom in NO3- is
A. p3.
B. sp2.
C. sp.
D. sp2d.
E. sp.
2015-08-16 21:59:17 · answer #5 · answered by ? 1 · 0⤊ 0⤋
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N3- no need of hybridisation. it is a monoatomic ion. No need of structure again. CO3- the hybridisation is sp2 on carbon. it is trigonal planar. NO3- too is trigonal planar. Hybridisation is sp2 again. In BF4- the hybridisation is sp3. And the shape is tetrahedral. Cheers
2016-03-27 02:12:58 · answer #6 · answered by ? 4 · 0⤊ 0⤋
I go with (b). One bond is a double bond, which is generally a sp2 outcome.
2007-04-06 14:52:59 · answer #7 · answered by cattbarf 7 · 0⤊ 0⤋
its either sp2 or sp3, since sp3 is not there, then sp2
B
2007-04-06 15:08:27 · answer #8 · answered by Anonymous · 0⤊ 0⤋