Sigma notation?

0 ⤊

1/(1*2)+1/(2*3)+1/(3*4)+...+1/(119*120)
A
Σ B
n=1

A=?
B= 1/(n*(n+1)) (<--i KNOW that is right)

2007-04-06 13:26:45 · 3 answers · asked by bebe_love_xo 1 in Science & Mathematics ➔ Mathematics

3 answers

A = n*(n+1)
B = 1/(n*(n+1))

2007-04-06 14:29:07 · answer #1 · answered by M. Abuhelwa 5 · 0⤊ 0⤋

A is just the value where you want the sum to end. So if you wanted 4 terms so that it would stop at 1/(4*5), A would equal 4.. etc for where you want the sum to end

2007-04-06 20:50:02 · answer #2 · answered by Jhsiao 2 · 0⤊ 0⤋

A = any positive integer that you wish. It can even be infinity.
If A = infinity then Î£ B is an infinite series.

2007-04-06 21:03:36 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋