5>3 and 5<10
What is the formula to verify and how, to me it seems to be true because 5 is greater than 3 and 5 is less than 10.
2007-04-06 09:56:03 · 11 answers · asked by gixxer6i9 1 in Science & Mathematics ➔ Mathematics
It is true, not quite sure how you would "verify", but if you change 5>3 by subtracting 3 from both sides 2 > 0. All positive numbers are greater than 0 so this is true. Same for the second one, but subtract 5 from both sides and get
0 < 5 which is also true for the same reason.
2007-04-06 09:59:52 · answer #1 · answered by Anonymous · 0⤊ 0⤋
3 < 5 < 10
2007-04-06 09:59:55 · answer #2 · answered by John 2 · 0⤊ 0⤋
First of all, it's not an equation. It's a pair inequalities arranged in a statement, "5>3 and 5<10".
Second of all, the statement is true. I don't know what kind of "formula" you're expecting. If you have an "AND" statement, and what's on both sides of the "AND" are true, then the whole thing is true. If you had "5>3 or 5>10", that would be true too, since the "OR" implies only one of the statements inside has to be true.
2007-04-06 10:03:06 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Yes, this equation is true because 5 is greater than 3 and less than 10.
3<5<10
2007-04-06 10:29:48 · answer #4 · answered by Groo-V 2 · 0⤊ 0⤋
You can change the order of the first inequality and combine the two inequalities.
3<5<10 which is only true if 3<10. It's true.
2007-04-06 10:01:28 · answer #5 · answered by ecolink 7 · 0⤊ 0⤋
Break it down and solve it in chunks:
5 > 3 -- True
5 < 10 -- True
(true) and (true) -- True
If you are unsure of the "and" operator, just refer to its truth table:
T and T = T
T and F = F
F and T = F
F and F = F
2007-04-06 10:01:45 · answer #6 · answered by computerguy103 6 · 0⤊ 0⤋
5>3 is true
5<10 is true
true and true = true
2007-04-06 10:00:56 · answer #7 · answered by Hari 1 · 1⤊ 0⤋
For the finest one, the plan of attack must be to get the demoninator less than that divide signal to be 0. For the others, you fairly favor to easily try them, highly if that's your human being homework. i could advise in simple terms putting parenthesis in random places, then seeing what the outcome's, and checking that off the record, as adversarial to attempting to unravel for any certain answer in the starting up. when you've maximum of them, then you really can target the few that are lacking.
2016-11-26 23:31:45 · answer #8 · answered by Anonymous · 0⤊ 0⤋
If someone is asking you for a formula for these, listen to someone else! You have it right.
2007-04-06 10:02:10 · answer #9 · answered by Anonymous · 0⤊ 0⤋
What you think is positively correct
2007-04-06 10:52:27 · answer #10 · answered by me and just me 2 · 0⤊ 0⤋