Sketch the region D in the x-y plane when X²+ Y² greater equal than 1?

Answer 1

x^2 + y^2 = 1 is a circle of radius 1 that is centered at the origin.

So, D is everything OUTSIDE that circle.

Answer 2

If you mean X^2 + Y^2 is greater than or equal to 1
X^2 + Y^2 >= 1, then:

D is the region of the plane on the outside of and including the circle graph. The circle is of radius 1 with center at the origin.

If you didn't mean =1 then the graph of the circle is not included.

Answer 3

X^2 + Y^2 >= 1, then:

D is the region of the plane on the outside of and including the circle graph. The circle is of radius 1 with center at the origin.

Answer 4

It is the region of the x-y plane outside the circle x^2+y^2=1

Answer 5

draw a circle with the center at the origin at (0,0) with a radius of 1. Then region D includes the border of the circle and the area outside of the cricle borders.

Answer 6

(x,y)=x^2+2y^2-xy^2, solid success (: ! ahaah :-p permit f(x,y)=x^2+2y^2-xy^2. Use the attempt for Relative intense to discover any relative extrema or saddle factors and detect the kind of relative extremum employing the attempt for Relative Extrema.