2007-04-06 06:49:58 · 6 answers · asked by mao z 1 in Science & Mathematics ➔ Mathematics
Point-Slope form:
when you have a slope of m and a point (x1, y1), use the equation...
y - y1 = m(x - x1)
So...
y - 3 = 2(x - 0)
y - 3 = 2x
y = 2x + 3
2007-04-06 06:55:30 · answer #1 · answered by Mathematica 7 · 0⤊ 1⤋
Simple. For x = o, y = c in the equation y = mx + c and since the line goes through (0,3), c = 3. Since slope is 2, we have m = -2. So the equation is
y = -2x + 3
2007-04-06 13:58:54 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
Use the formula:
m= -2 , y1= 3, x1=0
y-y1=m(x-x1)
y-3 = (-2)(x-0)
y-3 = -2x
Add 3 to both sides
y= -2x + 3
2007-04-06 14:02:18 · answer #3 · answered by pya102 2 · 0⤊ 0⤋
Slope intercepy form
y = mx + b
3 = - 2(0) + b
3 = 0 + b
3 = b
y = - 2x + 3
- - - - - - - -s-
2007-04-06 14:15:48 · answer #4 · answered by SAMUEL D 7 · 0⤊ 0⤋
y = mx + b
y = -2x + 3
or in standard form it is
2x + y = 3
2007-04-06 13:55:53 · answer #5 · answered by CD 1 · 0⤊ 0⤋
y = mx + b
y intercept = (0.3)
m = slope = -2
y = -2x + 3
2007-04-06 13:53:32 · answer #6 · answered by Anonymous · 0⤊ 0⤋