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2007-04-06 06:32:19 · 11 answers · asked by Anonymous in Science & Mathematics Mathematics

11 answers

5 / √50 =

5 / √25 √2 =

5 / 5√2 =

1 / √2 =

1 √2 / √2√2 =

√2 / √4 =

√2 / 2

- - - - - - - - -s-

2007-04-06 08:31:38 · answer #1 · answered by SAMUEL D 7 · 0 0

Remember this rule of mathematics: You cannot have a square root in the denominator. So, let's look at the problem:

5
--------
√50

So, in order to get rid of this square root from the denominator, the easiest way to do it is to multiply the numerator and denominator of the fraction by √50. Let's do it. :)

5*√50
---------------
√50*√50

Now, (√x)²=x, so (√50)²=50. So, with the denominator simplified, our fraction is:

5√50
---------
50

Now, we need to simplify √50. An easy way to find this is to find the largest square root of a perfect square that can be multiplied by another square root of an integer to equal this square root. Now, remember this rule of mathematics: If both m and n are positive real numbers, then √m*√n=√mn. So, the largest square root of a perfect square multiplied by a square root of an integer that equals this square root is √25. √25*√2= √25*2= √50. So, since √25=5, √50= 5√2. So, putting that into the fraction, we get:

5*5√2
-----------
50

Further simplification produces:

25√2
----------
50

Now, 25 goes into 25 and 50. So, let's divide 25 into 25 and 50. We get:

1√2
--------
2

Simplified we get:

√2
-------
2

Which is your answer.

There you go. I'm glad I could help. :)

2007-04-06 14:37:32 · answer #2 · answered by iamanicecaringfriend 3 · 0 0

The only trick here is realizing that 50 can be factored into 25*2

so

5/sqrt(50) = 5/sqrt(25*2) = 5/(sqrt(25)*sqrt(2)) = 5/(5*sqrt(2))
= 1/sqrt(2)


Edit:
After posting my answer I looked at the other answers that you got. Please note that sqrt(2)/2 is exactly equal to 1/sqrt(2).

2007-04-06 13:37:43 · answer #3 · answered by dogsafire 7 · 0 0

5 over the sqrt of 50

50 = 25 X 2 so:

sqrt 50 = sqrt 25X2 = 5 sqrt 2

Original expression is:

5/(sqrt 50) = 5/(sqrt 25X2) = 5/(sqrt 25)(sqrt 2) =

5/[5(sqrt 2)] = 1/(sqrt 2)

or 1 over (sqrt 2)

2007-04-06 13:39:45 · answer #4 · answered by Mario 3 · 0 0

5 /√50 = 5 /√[(25)(2)] = 5 /5√2

Divide out the 5 from both the numerator and denominator:

5 /5√2 = 1 /√2

Rationalize the denominator by multiplying the whole fraction by √2 /√2:

1 /√2(√2 /√2) = √2/(√2)² = √2 /2

Your final answer is (√2) /2

2007-04-06 13:50:24 · answer #5 · answered by MathBioMajor 7 · 1 0

√50 = √25 * 2 = √5^2 * 2 = 5√2

5/(5√2)

Multiply by (5√2) / (5√2)

5 * 5√2
-------------
5√2 * 5√2

(25√2) / 50 = (√2) /2

2007-04-06 13:37:43 · answer #6 · answered by its_victoria08 6 · 0 0

5/sqrt(50) = 5/[sqrt(5)*sqrt(10)] = sqrt(5)/sqrt(10) =
= sqrt(5)/sqrt(5 * 2) = 1/sqrt(2) = sqrt(2)/2

2007-04-06 13:36:20 · answer #7 · answered by Amit Y 5 · 1 0

sqrt (50) = sqrt (25*2) = sqrt (25) * sqrt (2) = 5 * sqrt (2)

2007-04-06 13:35:33 · answer #8 · answered by galaxy_gazing_girl 4 · 0 1

5/sqrt(50)
= 5/[sqrt(5)*sqrt(5)*sqrt(2)]
= 5/[5*sqrt(2)]
= 1/sqrt(2), or
= sqrt(2)/2

2007-04-06 13:46:24 · answer #9 · answered by Kyrix 6 · 1 0

5 / sq rt 50

= 5 / sq rt (25*2)

= 5 / sq rt (5^2 * 2)

= 5 / (5 * sq rt 2)

= 1 / sq rt 2 [since 5/5 = 1]


...If you still have to rationalize, multiply that by sq rt 2/sq rt 2

(1 / sq rt 2) * (sq rt 2 / sq rt 2)

= (sq rt 2) / 2 [ (sq rt 2)*(sq rt 2) = 2]

:D

2007-04-06 13:42:14 · answer #10 · answered by Dazeddd 2 · 0 1

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