The ratio of the perimeters of two similar figures is 4:121. If the lenght of one side of the smaller figure is 22 cm, what is the lenght of the corresponding side of the larger figure?
2007-04-06 06:31:44 · 7 answers · asked by Juan C 6 in Science & Mathematics ➔ Mathematics
The figures are similar, so if the perimeters have the ratio 4:121, all other corresponding lengths have the ratio 4:121, too.
So if the side in the smaller figure is 22, it has to be (22 : 4) * 121 = 665.5 in the other one, because 22 : 665.5 = 4 : 22.
2007-04-06 06:38:08 · answer #1 · answered by galaxy_gazing_girl 4 · 1⤊ 0⤋
the ratio 4:121 means that
P of the smaller figure = multiple of 4
P of the larger figure = multiple of 121
Small P/Large P = Small side/Large side
4/121 = 22/x
cross multiply...
4(x) = 22(121)
4x = 2662
x = 665.5
2007-04-06 06:36:27 · answer #2 · answered by Mathematica 7 · 1⤊ 0⤋
it would be 4/22 equals 121/x so 4x= 121times 22 by cross multiplying so 2662=4x
2662/4 =x
so x =665.5
2007-04-06 07:21:42 · answer #3 · answered by Anonymous · 1⤊ 0⤋
Let x be the length of the larger figure.
By proportionality, we have
4:121 = 22:x
Solve for x,
x = 665.5 cm
2007-04-06 06:36:13 · answer #4 · answered by sahsjing 7 · 1⤊ 0⤋
4/121=22/x 4x= 2662 x=665.5
2007-04-06 06:37:32 · answer #5 · answered by bruinfan 7 · 1⤊ 0⤋
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2016-10-02 06:57:23 · answer #6 · answered by ? 4 · 0⤊ 0⤋
4 : 121 = 22 : x =
4x = 22(121) =
4x = 2662 =
4x / 4 = 2662 / 4
x = 2662 / 4
x = 665.5
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2007-04-06 08:46:10 · answer #7 · answered by SAMUEL D 7 · 1⤊ 0⤋