3y = -2x + 12
y = (-2/3)x + 4
This is the equation of a straight line having slope of -2/3 (the graph drops down 2 units for every 3 units one moves to the right). It intersects the y-axis at y = 4 and the x-axis at x = 6.
2007-04-06 06:37:42
·
answer #1
·
answered by MathBioMajor 7
·
0⤊
0⤋
2x +3y = 12
x = 0 => y=4; y=0 => x=6. So it's the line passing through points (0,4) and (6,0). Just draw it
2007-04-06 13:38:42
·
answer #2
·
answered by Evgeniy E 3
·
0⤊
0⤋
x = 0
2x + 3y = 12
2(0) + 3y = 12
3y = 12
3y/3 = 12/3
y = 4
- - - - - - - -
y = 0
2x + 3y = 12
2x + 3(0) = 12
2x + 0 = 12
2x = 12
2x/2 = 12/2
x = 12/2
x = 6
- - - - - - - - -
y intercept
2x + 3y = 12
2x + 3y - 2x = - 2x + 12
3y = - 2x + 12
3y / 3 = - 2x / 3 + 12 / 3
y = - 2/3x + 4
- - - - - - - - -
x intercept
2x + 3y = 12
2x + 3y - 3y = - 3y + 12
2x = - 3y + 12
2x / 2 = - 3y / 2 + 12 / 2
x = - 3/2y + 6
- - - - - - - - - s-
2007-04-06 16:12:00
·
answer #3
·
answered by SAMUEL D 7
·
0⤊
0⤋
x=0,y=4,,,,,,,,,x=6,y=0,,,,
x=1,y=10/3,,,,x=9/2,y=1
y=m x +n ,,m=slope =-2/3,n=4
y-4/x =m
..(y-0)-4/(x-0)=-2/3
3y-12=-2x
2007-04-07 06:33:26
·
answer #4
·
answered by Tuncay U 6
·
0⤊
0⤋