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2007-04-06 06:28:24 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

3y = -2x + 12
y = (-2/3)x + 4

This is the equation of a straight line having slope of -2/3 (the graph drops down 2 units for every 3 units one moves to the right). It intersects the y-axis at y = 4 and the x-axis at x = 6.

2007-04-06 06:37:42 · answer #1 · answered by MathBioMajor 7 · 0 0

2x +3y = 12
x = 0 => y=4; y=0 => x=6. So it's the line passing through points (0,4) and (6,0). Just draw it

2007-04-06 13:38:42 · answer #2 · answered by Evgeniy E 3 · 0 0

x = 0

2x + 3y = 12

2(0) + 3y = 12

3y = 12

3y/3 = 12/3

y = 4

- - - - - - - -

y = 0

2x + 3y = 12

2x + 3(0) = 12

2x + 0 = 12

2x = 12

2x/2 = 12/2

x = 12/2

x = 6

- - - - - - - - -

y intercept

2x + 3y = 12

2x + 3y - 2x = - 2x + 12

3y = - 2x + 12

3y / 3 = - 2x / 3 + 12 / 3

y = - 2/3x + 4

- - - - - - - - -

x intercept

2x + 3y = 12

2x + 3y - 3y = - 3y + 12

2x = - 3y + 12

2x / 2 = - 3y / 2 + 12 / 2

x = - 3/2y + 6

- - - - - - - - - s-

2007-04-06 16:12:00 · answer #3 · answered by SAMUEL D 7 · 0 0

x=0,y=4,,,,,,,,,x=6,y=0,,,,
x=1,y=10/3,,,,x=9/2,y=1
y=m x +n ,,m=slope =-2/3,n=4
y-4/x =m
..(y-0)-4/(x-0)=-2/3

3y-12=-2x

2007-04-07 06:33:26 · answer #4 · answered by Tuncay U 6 · 0 0

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