what is the balanced nuclear equation for the radioactive decay of thorium 230:?

Question

with emmission of an alph particle...

i understnad how to do unless the atmoic mass and the atomic number is given....what is the atomic number for thorium 230?....explanation plz

Answer 1

thorium loses an alpha particle

Find the element that has 2 fewer protons and subtract 4 from the 230 atomic mass.

Answer 2

Decay by alpha particle results in 4 units loss in mass and 2 units loss in proton number.

thus thorium decays by loss of alpha particles forming radium:

230 Th 90 --------> a + 226 Rn 88.

Answer 3

seventy 4 W 178 ===> seventy two Hf 174 + 2He4 E = 3.2 mev seventy 4 W 185 ===> seventy 5 Re 185 + e- E = 0.428 mev seventy 4 W 181 + e- ===> seventy 3 Ta 181 + 2 gamma rays E = 0.136, 0.152 mev ("+ e-" denotes seize of an exterior electron via the W-181 nucleus.)