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I have a polygon. The there are five side and each angle is as follows:
angle = a
angle = a+10

angle = 120
angle= 130

I need to find a?
Do I do the same as a quadilateral? Or do I break it into triangle? Confused?

2007-04-06 06:02:28 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

I'm pretty sure that all the angles in a polygon of any number of sides is always equal to 360, except triangles, who's angles add to 180. (I couldn't remember if triangles were considered polygons or not.)

So, add your angles together and set that equal to 360 and solve.

It looks like you are missing an angle... but I've told you how to do it, so you should be able to figure it out.

Yes, for a quadrilateral, you would set the sum of all angles equal to 360 and solve.

You don't have to break it into a triangle. That would just add more work. :o)

2007-04-06 06:09:04 · answer #1 · answered by its_victoria08 6 · 0 0

Since all the angles must add up to 360, 2a+260=360
or 2a=100 a=50.

2007-04-06 13:17:04 · answer #2 · answered by bruinfan 7 · 0 0

i appreaciate ur eagerness
but then the unknown variable wont remain unknown

2007-04-06 13:06:19 · answer #3 · answered by karan289 2 · 0 0

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