I have a quadrilateral. The four corners are as follows:
angle = x
angle = x
angle = x-30
angle = x-40
I need to find out what x is?
I am lost !
2007-04-06 05:43:25 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
All four angles of the quadrilateral will equal 360.
Therefore, x + x + (x-30) + (x-40) = 360
4x - 70 =360
4x = 430
x=107.5
The angles are: 107.5, 107.5, 77.5, 67.5
2007-04-06 05:49:55 · answer #1 · answered by trojanknight_96 3 · 0⤊ 0⤋
The sum of angles in a quadrilateral is 360 degrees. Therefore, you simply need to solve x + x + x - 30 + x - 40 = 360, which simplifies to 4x - 70 = 360, a straightforward algebra problem.
2007-04-06 05:47:25 · answer #2 · answered by DavidK93 7 · 0⤊ 0⤋
The angles sum to 360. Thus:
x + x + x-30 + x-40 = 360
Solve for x.
Good luck!
2007-04-06 05:47:23 · answer #3 · answered by tedfischer17 3 · 0⤊ 0⤋
Must add to 360, x+x+(x-30)+(x-40)= 360
4x-70=360
4x=430
x= 107.5
2007-04-06 05:50:24 · answer #4 · answered by dothedew9231 2 · 0⤊ 0⤋