2007-04-06 02:34:30 · 4 answers · asked by Rose Mary T 1 in Science & Mathematics ➔ Mathematics
Put them in numerical order. The smallest is the minimum. The largest is the maximum.
2007-04-06 02:49:43 · answer #1 · answered by John S 6 · 1⤊ 0⤋
If there are only 4 numbers, it is easy to see the minimum and maximum by simple inspection. If not, you can do this:
Let n1, n2, n3 and n4 be the four numbers.
If n1 - n2 = + ve, n1 is greater than n2, if 0, n1 is equal to n2 and if -ve, n1 is lesser than n2.
If n1 > (greater than) n2, continue with n1 - n3. If n1 = n2, continue with n2 - n3. If n1 < (less than) n2, continue with n2 - n3.
Repeat the above algorithm, till all numbers have been exhausted.
Finally list the numbers in the decreasing order. The first number is maximum and the last number is minimum.
2007-04-06 10:08:01 · answer #2 · answered by Swamy 7 · 0⤊ 0⤋
Try to get a decimal approximation of those numbers
ex:sqrt2 =1.4142...
2007-04-06 09:48:49 · answer #3 · answered by santmann2002 7 · 0⤊ 0⤋
Maximum: Biggest number
Minimum: Smallest number
Please give me best answer thanks!
2007-04-06 09:49:24 · answer #4 · answered by Anonymous · 1⤊ 0⤋