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1 liter of that solution has a mass of 1.202g for 1 ml or 1202g/L

the mass of KI is (1.202*20)/10 =240.4g of KI
the mass of water is 1202-240.4=961.6g of water

we caculate now the number of moles of KI
b)mass molar of Ki =39+127 =166 and 240.4/166= 1.45 mole Ki

the number of mole of water is 961.6/18=53.42) = moles H2O

We caculate molality of KI = number of moles by kg solvent

here we have 1.45 mole for 0.9616kg of water
so1.508mole/kg off water

the molarity of KI = mole/Liter you have 1.45

Molar fraction = mole solute /(mole solute +mole solvent)

x = 1.45/(1.45+53.42) =0.0275(mole KI/mole ki+mole water)

2007-04-05 22:32:28 · answer #1 · answered by maussy 7 · 0 0

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