Given the numbers as measurements of the sides of a triangle, for which of the following can a triangle exist?

Question

Is It:

8,6,10

16,18,25

7,7,7

Answer 1

*8,6,10 sides of a triangle is possible as,
8+6>10.
14>10.
*16,18,25 sides of a triangle is possible as,
16+18>25
34>25
*7,7,7 sides of a triangle is possible as,
7+7>7.
14>7
In short , it is a basic condition that sum of two smaller sides should be greater than bigger side for the triangle to be existed.
*you can draw your self with the help of a scale,compass and pencil if you dont have knowledge of basic rules.
*you can device your own rule by practicing.
Read the following:
[The instructor discussed the course and collected student information. Brief explanation of why the study of calculus in Rn rather than just R2 or R3 might be interesting was given.
Presentation of rectangular coordinate systems (how to locate points) in R1 (the real line), R2 (the plane), and R3 (space), followed by generalization to Rn.
Distance introduced: this is a nonnegative real number. On the line, the distance between p and q, if these have coordinates a and b, say, is |a-b| or sqrt((a-b)2). "Simple" properties of this distance were given:
The distance from p to p is 0.
The distance from p to q equals the distance from q to p.
The distance from p to r is less than or equal to the distance from p to q + the distance from q to r.
The first two properties were "clear" and the last needed some discussion. An example was given to show that equality is not necessarily correct.
A distance formula in R2 was suggested using the Pythagorean Theorem: the square root of the sum of the squares of the differences in coordinates of the points. Verification of the first two properties of distance for the plane suggested by those of the line was immediate. A rather lengthy algebraic verification of the third property was given. A sequence of reversible algebraic steps was applied to the inequality suggested until a statement about squares being nonnegative was obtained.
*Generalization of the formula to Rn was given. A name was given to the third property of distance:
the triangle inequality, and an appropriate picture was drawn:

Geometrically, the length of one side of a triangle is "clearly" less than or equal to the sum of the lengths of the other two sides. ]

Answer 2

The answer is letter d. because of the triangle inequality theorem that states that if a, b, c are the lengths of the sides of a triangle: a-b

Answer 3

Pythagorean Theorem

8, 6, 10

c² = a² + b²

√c² = ± √(8) + (6)

√c² = ± √64 + 36

√c² = ± √100

c = ± 10

This is a Triangle

- - - - - - - -s-

Answer 4

All three.
The first one is a right-angled triangle.
The second one is a scalene triangle (i.e., a triangle with unequal sides).
The third one is an equilateral triangle.

Answer 5

8, 6, 10

Answer 6

it is obvious that all of them can exist
to make sure that a triangular can exist the sum of any two sides must be larger than the other side which true for all your giving triangular.
you can check it by drawing them by Auto CAD

Answer 7

All of them....Anas, Jay5, and asphyxia seem to be the only sign of intelligence in here! The rest of you need to take beginner math!

Answer 8

a) 8, 6, 10....but don't quote me on it!!! It's been a while!

Answer 9

8,6,10
it is a^2 + b^2 = c^2

Answer 10

im pretty sure 7,7,7 can... its equilateral.
i think all of em are possible.