Ok...
3/(3-A) = B/A
Any help please.. I just want assistance, I have a huge test in the morning and I am ok with these types of problems but this one has me stumped.
2007-04-05 20:03:01 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Solving for A... sorry
2007-04-05 20:18:44 · update #1
Singing Rose.....
I think u are right but I am confused about one part, that is probably affecting the answer.
At the second part:
(A)(3) = (3-A)(B)
3A = (3)(B) - (3)(A)********
3A = 3B - 3A
Wouldn't it be 3A=3(B)-AB?
This is what was throwing me off and why I can't solve the problem. How do I get rid of the A in the AB part. or if you are right can u please help me understand. I will have the right answer in like 2 hours and i will post it... But i just want to know in case one of these pops up on my exam!
2007-04-06 04:52:01 · update #2
1. Solve for the "A" variable....
3/(3-A) = B/A
1st: eliminate the fractions by multiplying the denominators with each term.
(A)(3-A)[3/(3-A)] = (A)(3-A)(B/A)
2nd: cross cancel "like" terms (eliminate the same terms) & combine the remaining terms.
(A)(3) = (3-A)(B)
3A = (3)(B) - (3)(A)
3A = 3B - 3A
3rd: combine "like" terms (combine coefficients with the same variable). add 3A with both sides (when you move a term to the opposite side, always use the opposite sign).
3A + 3A = 3B - 3A + 3A
3A + 3A = 3B
6A = 3B
4th: solve for "A" by isolating it on one side - divide both sides by 6.
6A/6 = 3B/6
A = 3B/6
*Simplify the coefficients into lowest terms > 3/6 = 1/2
A = 1B/2 or A = B/2
2007-04-06 03:05:45 · answer #1 · answered by ♪♥Annie♥♪ 6 · 1⤊ 1⤋
this is a proportion type of a question and to solve it,you need to cross multiply:
3A = (3 - A)B
3A = 3B - AB
I am going to guess here that you wish to solve for A, so we are going to move AB to the other side of the equation by adding:
3A + AB = 3B
factor: A(3 + B) = 3B
divide by (3 + B): A = 3B / (3 + B )
typically proportions are with one variable, so you would get a numerical answer as a solution
good luck on your test.
2007-04-06 03:09:26 · answer #2 · answered by Ana 4 · 0⤊ 1⤋
You could cross multiply:
3A = B(3 - A) and then expand, but I what are you trying to do? Are you solving in terms of A or B?
2007-04-06 03:09:20 · answer #3 · answered by birdwoman1 4 · 0⤊ 1⤋
You won't get a numerical answer on this one. You have two unknowns and only one equation. The best you can do is
B = 3A/(3 - A)
2007-04-06 03:15:53 · answer #4 · answered by Helmut 7 · 0⤊ 1⤋
Tiger is wrong.
You've got to cross multiply. 3A - 3B + AB =0
2007-04-06 03:11:14 · answer #5 · answered by Anonymous · 0⤊ 1⤋
3 / (3-A) = B / A
Cross Multiplication
B = 3A / (3-A)
2007-04-06 03:09:53 · answer #6 · answered by shahidrock 3 · 1⤊ 1⤋
A(3-A)=3B
A3-A^2=3B
2007-04-06 03:05:36 · answer #7 · answered by Anonymous · 0⤊ 2⤋
Are you trying to solve for A or B?
There is no finite answer since this involves two unknowns and only one equation.
2007-04-06 03:08:58 · answer #8 · answered by i_sivan 2 · 0⤊ 1⤋
B=3A/(3-A)
or
A=B/A
maybe even
1=B/2A
2007-04-06 03:13:33 · answer #9 · answered by Anonymous · 0⤊ 1⤋
ok, its been like 6 years since i've had to do any of this, but i think i have it
3/(3-A)=B/A
(3/3)-(3/A)=B/A
A(1-3/A)=(B/A)A
A-3=B
A=B+3
I hope it was some help ... dont hold me to that answer though
2007-04-06 05:53:12 · answer #10 · answered by ambski02 1 · 0⤊ 1⤋