multiplying polynomials!!!!!?

Question

i need some help on multiplying polynomials can you please help me! i dont understand it at all! and can u show ur work and simplify!!!

1) 3x(x+9)

2) 5mn(7m-2n)

3) 3xy(-x to the power of 4-4x to the power of 2 y+5xy to the power of 2)

4) (x/5) (x/3)


thank you soooooo much! if you help me out and its correct ill get u 10 pts!!!

Answer 1

1) you distribute the 3x
(3x(x))+(3x(9))
3x^2+27x

2) distribute the 5mn
(5mn(7m))+(5mn(-2n))
35m^2n-10mn^2

3) i dont understant what the problem looks like

4) just multiply them
(x/5)(x/3)=x^2/15

FYI: x^2 means x squared, or x to the 2nd power, and so on..

Answer 2

3x times the x, and 3x times 9. That's 3xx + 3x9. Simplify the 3x9: it is 27x. So you have 3xx + 27x.


5mn times both the 7m and the -2n. That's 5mn7m, or 35nmm; and 5mn(-2n), or -10mnn. Combined it is 35mmn - 10mnn.


3xy raised to [(-x)(4-4x)(2y + 5xy)(2)].

First multiply the (-x) by (4 - 4x). That is -4x + 4xx.

Then multiply the (-4x + 4xx) by (2y + 5xy). Step by step, first the -4x multiplies the 2y and the 5xy, then the 4xx does the same thing. -4x2y - 4x5xy + 4xx2y + 4xx5xy. Simplify and get this:
-8xy - 20xxy + 8xxy + 20xxxy.

The 2 has a doubling effect:
-16xy - 40xxy + 16xxy + 40xxxy. You can combine -40xxy with 16xxy and get -24xxy. Here it is: -16xy -24xxy + 40xxxy. Put it in a conventional order: 40xxxy - 24xxy - 16xy.

3xy raised to (40xxxy -24xxy -16xy).




The last one is a multiplication of numerators, and then denominators: [xx/(5 X 3)] = xx/15.

Answer 3

1) 3x(x+9)
3x^2 + 27x
2) 5mn(7m-2n)
35m^2n - 10mn^2
3) 3xy(-x to the power of 4-4x to the power of 2 y+5xy to the power of 2)
o.k. the best I can do is 3xy - x^[{4 - 4x}^((2y + 5xy)^2)}
4) (x/5) (x/3)
x^2/15
I have tried my best and I have never seen the third question. Alas I have attempted my best.
Yours Truly,

edexter93

Answer 4

to multiply polynomials, we are going to use distributive property
1) 3x(x + 9) = 3x*x + 3x*9 = 3x^2+27x
(we add exponents when multiplying terms with the same base, thus the reason for x^2 term)

2) 5mn(7m - 2n) = 5mn*7m - 5mn*2n = 35m^2n - 10mn^2
(we multiply number with number and variable with variable)

3) 3xy(-x^4 - 4x^2y + 5xy^2) = 3xy*(-x^4) - 3xy*4x^2y + 3xy*5xy^2 = 3x^5y - 12x^3y^2 + 15x^2y^3

4) (x/5)(x/3) = x^2/15
to multiply fractions, we need to multiply numerator with a numerator and denominator with a denominator

hope this helps. also, just to clarify - " ^ " means raised to a power and " * " means multiplication

Answer 5

Its simply a matter of distributing the outside term into the inside terms; do it term by term

1) 3x(x+9) = 3x^2+27x

2) 5mn(7m-2n) = 35(m^2)n-10m(n^2)

4) (x/5) (x/3) = (x^2)/15

You'll have to clarify on question 3.

Answer 6

1. 3x(x + 9)

1st: eliminate parenthesis by using the Distribution Method - multiply the outer term with the terms in parenthesis.

(3x)(x) + (3x)(9)

3x^2 + 27x

2. 5mn(7m - 2n)

1st: (same as #1) - use the Distribution Method > multiply the outer term with the terms in parenthesis.

(5mn)(7m) + (5mn)(-2n)

35m^2n + (-10mn^2)

35m^2n -10mn^2

3. Please, check your book to make sure you typed the problem correctly.

4. (x/5)(x/3)

1st: multiply the numerators & denominators.

(x)(x)/(5)(3)

x^2/15

Answer 7

1) 3x*x+ 3x*9
3x to the power 2+27x

2) 35m to the power of 2 n-10mn to the power of 2

Answer 8

to 5? i bypass to anticipate it rather is a '+' a million) x^2 +3x +5 +x^2 +4x+a million 2x^2 +7x +6 2) 6x(x^3 +5x^2 +3x +a million) 6x^4 +30x^3 +18x^2 +6x 3) 4(2x^2+3x^2y +5xy^2 +3y^2) 8x^2 +3x^2y +20xy^2 +12y^2

Answer 9

1) 3x^2+27x

2) 35m^2 n-10mn^2


4) x^2/15

Answer 10

1. 3x * x = 3xsquared
3x * 9 = 27x so (3xsquared +27x )is your answer