Free earlobes is dominant to attached earlobes. A man with attached earlobes and a woman who is heterozygous?

Question

have a child. What is the probability of their first child having attached earlobes?

a. 0%
b. 25%
c. 50%
d. 75%
e. 100%

please help. thanks.

Answer 1

aa(attached earlobes) x Aa(heterozygous- free earlobes)
the offsprings-
Aa(free)
aa(attached)
in the ratio 1:1
therefore the probability of the child having attached earlobed is 50%
c.

Answer 2

C. 50% - heterozygous when crossed with homozygous recessive will create a 50-50 Punnett Square.

Answer 3

Use F for free and f for attached.

Man is ff
Woman is Ff (Heterozygous means the letters don't match.)

ff x Ff
Boxes of Punnett square are fF, fF, ff, ff.
Probability of a child with attached earlobes (ff) is 2/4 which is 50%.

Answer is C.

Answer 4

i just did stuff like this a few weeks ago =)

so if you have atached, then that means that you have both recessive allele for that traits
if you're heterozygous then you have both recessive and dominant

there's a fifty chance of getting free, since the father only has reccessive and the woman has one reccessive and still has the possibilty of getting attached
there's also a fifty chance of getting attached since the woman is heterozygous and has the dominant trait


so basically their probability of getting attached is 50%

Answer 5

50%

Answer 6

c. 50% really the man doesn't matter it is up to the women who has a fifty fifty shot with the dominant gene. She has a fifty-fifty shot because she is heterozygous.

Answer 7

c. 50%

I have one attached earlobe and my other isn't attached, so I am a genetic oddity.

Answer 8

the answere is
d.50%

Answer 9

c. 50%