A man who is heterozygous for tongue rolling and has normal vision and a woman who?

Question

cannot roll her tongue and is heterozygous for colorblindness have a child. What is the probability that it will be able to roll his/her tongue have have normal vision?

a. 3/8
b. 3/16
c. 1/16
d. 1/4
e. 1/8

please help thanks.

Answer 1

RrXY(man) x rrXx(woman)
considering the characters separately
since the father is heterozygous for the character(rolling tongue) there is 50% chance that it will be passed onto the child.
considering colour blindness
XY x Xx
the offsprings will be
XX(normal)
Xx(normal)
XY(normal)
xY(colour blind)
therefore the chances of the child being normal is 75%
combining the possibilities
1/2 x 3/4 = 3/8

Answer 2

Colorblindness is an X-linked recessive condition.

Man is Tt XBY where T is roll, t is nonroll, B is normal vision
Woman is tt XB Xb where b is colorblindness.

Put the man's gametes on the side of the Punnett square:
T XB
T Y
t XB
t Y

Put the woman's gametes across the top of the square:
t XB, t Xb, t XB, t Xb

Probability of a child with at least one T and at least one XB:
6 of the boxes on the Punnett square - 6/16 = 3/8

Answer 3

b. 3/16 it really depends on what the dominant trait is but assuming there is no dominant trait you would multiply 1/4 with 3/4 and get 3/16.