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tongue. Jill can't roll her tongue. If Jack and Jill have a child together, what is the probability it will be able to roll his/her tongue?

a. 1.0 (100%)
b. 0.75
c. 0.5
d. 0.25
e. 0 (no chance it can roll tongue)

please help. thanks.

2007-04-05 18:11:51 · 6 answers · asked by Anonymous in Science & Mathematics Biology

6 answers

jack could be a homozygous dominant or a heterozygote considering that it is dominant trait.
but since his mother couldn't roll her tongue it suggests that he is heterozygous as he must have recieved one recessive allele for the trait from his mother.
if he is heterozygous there is 50% chance that he will pass on the trait to his child.
Rr(jack) x rr(jill)
the offsprings-
Rr(can roll)
rr(cannot roll)
in the ratio 1:1.
therefore the answer is
c. 0.5.

2007-04-05 18:23:13 · answer #1 · answered by rara avis 4 · 0 0

Since Jack can roll his tongue, he is Tt or TT.
Since Jack's Mother is a nonroller, she is tt.
That means Jack is Tt because he got a t from Mom.

Jill can't roll her tongue. She's tt.

Jack x Jill is represented by Tt x tt.
Place their gametes on a Punnett square: T and t on the left side; t and t on the top.
The boxes in the square are: Tt, Tt, tt, tt.
The probability of a child being a tongue roller is 2/4 or 0.5.
The prob. of a child being a nonroller is also 2/4 or 0.5

Answer is C.

2007-04-05 18:18:39 · answer #2 · answered by ecolink 7 · 0 0

here are some clues to help you.

let's call the tongue-rolling allele B and all other alleles b.

is the dominant tongue rolling allele (B) on the X chromosome? how does jack's mom's lack of this B allele answer the question? hint: her genotype is bb, right?

based on this is Jack hemizygous (only one copy of the gene because it's on X and its allele is the B allele, B0), heterozygous (Bb) or homozygous (BB) for the tongue-rolling allele?

if Jill can't roll her tongue this means that she does or does not have the tongue-rolling allele? is her genotype most likely BB, Bb, or bb?

mendel's laws say if one parent is Bb and the other parent is Bb then there's a 50% chance for EACH parent that they will pass down either B or b.

you should be able to deduce the answer from these suggestions and hints. best of luck. i know you can do it.

2007-04-05 18:25:39 · answer #3 · answered by trivirgatus 2 · 0 0

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2016-12-03 09:17:42 · answer #4 · answered by Anonymous · 0 0

c

2007-04-09 06:56:58 · answer #5 · answered by teri g 1 · 0 0

c

2007-04-05 18:15:50 · answer #6 · answered by Anonymous · 0 0

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