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((sin^4 t-cos^4 t)/(sin^2 t cos^2t))= sec^2 t - csc^2 t

2007-04-05 17:55:19 · 4 answers · asked by Weather dude 1 in Science & Mathematics Mathematics

4 answers

(sin^4 t-cos^4 t)/(sin^2 t cos^2t)
= (sin^2 t + cos^2 t) (sin^2 t - cos^2 t) / (sin^2 t cos^2 t)
= (1)(sin^2 t - cos^2 t) / (sin^2 t cos^2 t)
= sin^2 t - cos^2 t / (sin^2 t cos^2 t)
= sin^2 t / (sin^2 t cos^2 t) - cos^2 t / (sin^2 t cos^2 t)
= 1 / cos^2 t - 1 / sin^2 t
= sec^2 t - csc^2 t

2007-04-05 18:50:49 · answer #1 · answered by seah 7 · 1 0

sin^4 t - cos^4 t = (sin^2 t - cos^2 t)(sin^2 t+ cos^2 t) = sin^2 t- cos^2 t as sin^2 t+ cos^2 t =1

so LHS = (sin^2 t- cos^2 t)/ sin^2 t cos ^2 t

= 1/ cos^2 t - 1/sin ^2 t = sec^2 t- csc^2 t

2007-04-05 18:03:23 · answer #2 · answered by Mein Hoon Na 7 · 0 0

Prove the identity.

(sin^4 t - cos^4 t) / (sin²t cos²t) = sec²t - csc²t

Let's work with the left hand side.

Left Hand Side = (sin^4 t - cos^4 t) / (sin²t cos²t)

(sin²t + cos²t)(sin²t - cos²t) / (sin²t cos²t)

= (1)(sin²t - cos²t) / (sin²t cos²t)

= sin²t / (sin²t cos²t) - cos²t / (sin²t cos²t)

= 1 / cos²t - 1 / sin²t = sec²t - csc²t = Right Hand Side

2007-04-05 22:44:05 · answer #3 · answered by Northstar 7 · 0 0

csc x = one million/sin x cot x = one million/tan x csc^2x = one million/sin^2x cot^2x = one million/tan^2x (one million/sin^2x) - (one million/tan^2x) = one million (one million/sin^2x) - (one million/(sin^2x/cos^2x)) = one million (one million/sin^2x) - (cos^2x/sin^2x) = one million (one million-cos^2x)/(sin^2x) = one million (sin^2x/sin^2x) = one million one million = one million

2016-11-07 08:46:04 · answer #4 · answered by Anonymous · 0 0

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