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Prove Identities:
1. cos(theta)=1-2sin^2(theta)
2. sec(a-b)=(seca*secb)/(1+tana*tanb)

Please help me with these problems if you understand how to work them. Thanks

2007-04-05 15:09:51 · 4 answers · asked by ttumdg86 2 in Science & Mathematics Mathematics

sorry the 1st question is actually:
cos(2*theta)= 1-2sin(^2)theta

2007-04-05 15:29:26 · update #1

4 answers

1) cos(t) = 1 - 2sin^2(t) This is false.

Let t = -pi/2.
cos(-pi/2) = 0
1 - 2sin^2(-pi/2) = 1 - 2[-1]^2 = 1 - 2 = -1
0 is not equal to -1.

2007-04-05 15:17:47 · answer #1 · answered by Puggy 7 · 0 0

1. If theta is 90 degrees ( or pi/2 radians) then cos(theta) = 0, but 1-2sin^2(theta) = 1 - 2*(1^2) = -1

Not equal.

2.
If a = b and 0 < b < 45 degrees
then

sec(a-b) = 1

0 < sec(a)*sec(b) < 1
1 < 1+tana*tanb < 2

Therefore
(seca*secb)/(1+tana*tanb) < 1
not equal to sec(a-b) = 1

2007-04-05 22:21:44 · answer #2 · answered by Raymond 7 · 0 0

The first identity is not true as written; I think you left out a 2 somewhere. Probably to prove it you need to apply the general formula for cos(theta + phi).
The second formula did not come out; you need to add a space somewhere or Yahoo Answers won't display it properly.

2007-04-05 22:23:30 · answer #3 · answered by jiyuztex 2 · 0 0

try to check the identities again, write it clearly.

2007-04-05 22:21:36 · answer #4 · answered by oscar f 2 · 0 0

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